Answer:
Maximum area enclosed by the fence= 23,064 m²
Explanation:
Size of the fence used = 744m
Let the width of the fence be y
If the fence is divided into two by a fence running in parallel to one side of the fence, then the length, L = (744 - 3y)/2
Area enclosed by the fence, A = Length * Breadth
A = (744 - 3y)/2 * y
A = 372y - 1.5y²
At maximum area, A'(y) = 0
A'(y) = 372 - 3y
372 - 3y = 0
y = 372/3
y = 124 meters
Maximum area enclosed by the fence = 372(124) - 1.5*124²
A = 46128 - 23064
Maximum area = 23,064 m²
