Answer:
16.05% probability of 6 job applications received in a given week.
Step-by-step explanation:
When you have the mean during an interval, you should use the Poisson distribution.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Records show that the average number of job applications received per week is 5.9.
This means that [tex]\mu = 5.9[/tex]
Find the probability of 6 job applications received in a given week.
This is P(X = 6).
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 6) = \frac{e^{-5.9}*(5.9)^{6}}{(6)!} = 0.1605[/tex]
16.05% probability of 6 job applications received in a given week.
