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A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.3 N-s and the ball starts with an initial horizontal velocity of 3.8 m/s to the west and leaves with a 5.4 m/s velocity to the east, what is the mass of the ball (in grams)?

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opudodennis

Answer:

[tex]141.30grams[/tex]

Explanation:

First, denote our known values;

[tex]J=1.3N-s(+,east)\\u=-3.8ms^-^1(-,west)\\v=5.4ms^-^1(+,east)\\m=?[/tex]

Mass is impulse divided by change in velocity:

[tex]m=\frac{J}{v-u}\\=\frac{1.3}{5.4--3.8}\\\\=\frac{1.3}{9.2}\\=0.1413Kgs[/tex]

Hence, the mass of the ball is 141.30grams

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