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For a t distribution with 16 degrees of freedom, find the area (probability) in each region (do not round your answers): To the right of 2.120 Answer To the left of 1.337 Answer

Respuesta :

Answer:

[tex] P(t_{16} > 2.120)[/tex]

And we can calculate this with the complement rule, and with the following Excel code:

"=1-T.DIST(2.12,16,TRUE)"

And we got: [tex] P(t_{16} > 2.120)=0.024995 [/tex]

[tex] P(t_{16} < 1.337)[/tex]

And we can calculate this with the following Excel code:

"=T.DIST(1.337,16,TRUE)"

And we got:

[tex] P(t_{16} < 1.337)=0.900039 [/tex]

Step-by-step explanation:

For this case we know that we have a t distribution with df = 16

[tex] t (16)[/tex]

And we want this probability:

[tex] P(t_{16} > 2.120)[/tex]

And we can calculate this with the complement rule, and with the following Excel code:

"=1-T.DIST(2.12,16,TRUE)"

And we got: [tex] P(t_{16} > 2.120)=0.024995 [/tex]

For the other case we have this:

[tex] P(t_{16} < 1.337)[/tex]

And we can calculate this with the following Excel code:

"=T.DIST(1.337,16,TRUE)"

And we got:

[tex] P(t_{16} < 1.337)=0.900039 [/tex]

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