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The potential difference between two charged, parallel plates is 200 V and the distance between the plates is 360 cm. Calculate the electric field strength between the plates.

Respuesta :

Answer:

Explanation:

Given

Potential difference between the plates is [tex]V=200\ V[/tex]

Distance between the Plates [tex]d=360\ cm[/tex]

Electric Field between the Plates is given by

[tex]E=\frac{V}{d}[/tex]

[tex]E=\frac{200}{3.6}[/tex]

[tex]E=55.55\ V/m[/tex]

   

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