A 10-mm-diameter Brinell hardness indenter produced an indentation 2.50 mm in diameter in a steel alloy when a load of 1000 kg was used. Calculate the HB of this material.

Respuesta :

Answer:

[tex]HB \approx 200.484[/tex]

Explanation:

The Brinell Hardness is obtained from the following formula:

[tex]HB = \frac{2\cdot P}{\pi \cdot D^{2}}\cdot \left(\frac{1}{1 - \sqrt{1-\frac{d^{2}}{D^{2}} } } \right )[/tex]

Where [tex]P[/tex] is the load measured in kilograms-force, [tex]D[/tex] is the diameter of indenter measured in millimeters and [tex]d[/tex] is the diameter of indentation measured in millimeters.

[tex]HB=\frac{2\cdot (1000\,kgf)}{\pi\cdot (10\,mm)^{2}}\cdot \left[ \frac{1}{1-\sqrt{1-\frac{(2.50\,mm)^{2}}{(10\,mm)^{2}} } } \right ][/tex]

[tex]HB \approx 200.484[/tex]