Answer:
[tex]v_0=\frac{y}{t}-\frac{at}{2}[/tex]
[tex]v_0=49m/s[/tex]
Explanation:
We can start from the known formula:
[tex]y=y_f-y_0=v_0t+\frac{at^2}{2}[/tex]
so we can write, since we want the initial velocity in terms of the ball's displacement, its acceleration in the vertical direction, and the elapsed time:
[tex]v_0=\frac{y}{t}-\frac{at}{2}[/tex]
and for our values we have:
[tex]v_0=\frac{0m}{10s}-\frac{(-9.8m/s^2)(10s)}{2}=49m/s[/tex]