contestada

A 5.0 V battery storing 43.0 kJ of energy supplies 1.5 A of current to a circuit. How much energy does the battery have left after powering the circuit for 1.0 hr?

Respuesta :

Khoso123

Answer:

[tex]E_{remain}=16kJ[/tex]

Explanation:

Given data

[tex]V_{voltage}=5.0V\\I_{current}=1.5A\\E_{energy}=43.0kJ[/tex]

The Power is given as

[tex]P_{power}=V_{voltage}I_{current}\\[/tex]

Substitute the given values

[tex]P_{power}=5.0V*1.5A\\P_{power}=7.5W\\or\\P_{power}=7.5J/s[/tex]

In hour the energy is consumed is:

[tex]E{_1}=7.5J/s*(3600s)\\E{_1}=27000J\\E{_1}=27kJ\\[/tex]

So the energy left after one hour is:

[tex]E_{remain}=E_{energy}-E_{1}\\E_{remain}=43kJ-27kJ\\E_{remain}=16kJ[/tex]

asuwafohjames

The amount of energy left in the battery is 16000 J.

What is energy?

Energy is the ability of the capacity to do work.

To calculate the amount of energy left in the battery, we use the formula below.

Formula:

  • E' = E-VIt............ Equation 1

Where

  • E' = Amount of energy left in the battery
  • E = Energy stored in the battery
  • V = Voltage
  • I = Current
  • t = time.

From the question,

Given:

  • E = 43.0 kJ = 43000 J
  • V = 5 V
  • I = 1.5 A
  • t = 1 hr = 60 s.

Substitute these values into equation 1

  • E' = 43000-(5×1.5×60×60)
  • E' = 43000-27000
  • E' = 16000 J

Hence, the amount of energy left in the battery is 16000 J.

Learn more about energy here: https://brainly.com/question/2076038

Otras preguntas