Answer:t
Explanation:
A nozzle is a device where gas enters at high pressure and low velocity and exits at a low pressure and high velocity. It essentially works as an accelerator for gases. The work done by the gas is typically zero in a nozzle and if the nozzle is well-insulated, the process through the nozzle is typically adiabatic.
The following parameters are given to us in the problem statement.
{eq}\dot m = 3 \ kg/s \\ P_1 = 400 \ kPa \\ T_1 = 340 \ K \\ C_1 = 20 \ m/s
Answer:
The answers to the questions are
a). T₂ exit = 228.8 K
b). Area, A₂ exit = 15.66 cm²
Explanation:
a). γ/(γ-1)×P1/p1(1-(P₂/P₁)^((γ-1)/γ)) = V₁²/2-V₁²/2
Solving with P₁/p₁ = RT₁=290×340=98600
T₂/T₁=(P₂/P₁)^((γ-1)/γ) = (100/400)^((1.4-1)/1.4)
T₂/340 = 0.673 or T₂ = 340 × 0.673 = 228.8 K
T₂ = 228.8 K
b). Mass flow rate = 3 kg/s
Density ρ₁ = P₁/98600 = 400000/98600 = 4 kg/m^3
Volume flow rate = Mass flow rate/Density = 0.75 m³/s
Area = Volume flow rate/velocity = 0.75 m³/s/20 m/s = 0.0375 m²
A₁ ×v₂ =A₂×v₂
∴A₂ = 1.566×10^(-3) m³ =⁻15.66 cm²
