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A horizontal, uniform board of weight 125 N and length 4 m is supported by vertical chains at each end. A person weighing 500 N is sitting on the board. The tension in the right chain is 250 N. What is the tension in the left chain

Respuesta :

Answer:

Explanation:

Given

Weight of board [tex]W=125\ N[/tex]

Weight of person [tex]W_2=500 N[/tex]

Tension in the right chain is [tex]T_r=250\ N[/tex]

If board is in equilibrium then Net vertical force on it is zero

Suppose tension in the left chain is [tex]T_l[/tex] thus

[tex]T_l+T_r=W+W_1[/tex]

[tex]T_l=500+125-250[/tex]

[tex]T_l=375\ N[/tex]

     

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