Respuesta :
Answer:
[tex] \bar X = \frac{0.14+0.15+0.16+0.17+0.18}{5}= 0.16[/tex]
We can calculate the sample variance with the following formula:
[tex] s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}[/tex]
And replacing we got:
[tex] s^2 = 0.00025[/tex]
And the deviation is given by this:
[tex] s=\sqrt{0.00025}= 0.0158[/tex]
If we want to find the population deviation we just need to use this formula:
[tex] \sigma^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}[/tex]
And replacing we got:
[tex]\sigma^2 = 0.0002[/tex]
And the population deviation would be:
[tex] \sigma = 0.0141[/tex]
Step-by-step explanation:
For this case we have the following values:
0.14, 0.15, 0.16, 0.17, 0.18.
We can calculate the mean with the following formula:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex] \bar X = \frac{0.14+0.15+0.16+0.17+0.18}{5}= 0.16[/tex]
We can calculate the sample variance with the following formula:
[tex] s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}[/tex]
And replacing we got:
[tex] s^2 = 0.00025[/tex]
And the deviation is given by this:
[tex] s=\sqrt{0.00025}= 0.0158[/tex]
If we want to find the population deviation we just need to use this formula:
[tex] \sigma^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}[/tex]
And replacing we got:
[tex]\sigma^2 = 0.0002[/tex]
And the population deviation would be:
[tex] \sigma = 0.0141[/tex]
