contestada

You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abort the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 500 m with a radial acceleration of 18 m/s2 . What is the plane's speed?

Respuesta :

ikuemuyaolusegun

Answer: plane speed is 94.87m/s

Explanation: since the plane move upward in a semicircular path, the acceleration is a centripetal acceleration with radius of 500metre. But the Centripetal acceleration is given as

Centripetal acceleration

= Speed ²/radius

Making speed subject of formula we have,

Speed² = centripetal acceleration*radius

Speed² = 18*500

=9000

Speed =√9000

= 94.87m/s

hamzaahmeds

This question involves the concept of radial acceleration.

The plane's speed is "94.87 m/s".

RADIAL ACCELERATION

Radial acceleration of the plane can be given by the following formula:

[tex]a=\frac{v^2}{r}\\\\v=\sqrt{ar}[/tex]

where,

  • v = speed = ?
  • a = radial acceleration = 18 m/s²
  • r = radius of path = 500 m

Therefore,

[tex]v=\sqrt{(18\ m/s^2)(500\ m)}[/tex]

v = 94.87 m/s

Learn more about radial acceleration here:

https://brainly.com/question/7261283