A 2.35-g sample of an acid, H2X, requires 45.0 mL of a 0.500 M NaOH solution for complete reaction (removing both protons). The molar mass of the acid is: (Ignore significant figures for this problem.)

Respuesta :

Answer: The molar mass of [tex]H_2X[/tex] is 208.88 g/mol

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]

Molarity of NaOH solution = 0.500 M

Volume of solution = 45.0 mL = 0.045 L     (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

[tex]0.500M=\frac{\text{Moles of NaOH}}{0.045L}\\\\\text{Moles of NaOH}=(0.500mol/L\times 0.045L)=0.0225mol[/tex]

The chemical equation for the reaction of NaOH and [tex]H_2X[/tex] follows:

[tex]2NaOH+H_2X\rightarrow Na_2X+2H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of [tex]H_2X[/tex]

So, 0.0225 moles of NaOH will react with = [tex]\frac{1}{2}\times 0.0225=0.01125mol[/tex] of [tex]H_2X[/tex]

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of [tex]H_2X[/tex] = 2.35 g

Moles of [tex]H_2X[/tex] = 0.01125 moles

Putting values in above equation, we get:

[tex]0.01125mol=\frac{2.35}{\text{Molar mass of }H_2X}\\\\\text{Molar mass of }H_2X=\frac{2.35g}{0.01125mol}=208.88g/mol[/tex]

Hence, the molar mass of [tex]H_2X[/tex] is 208.88 g/mol

The molar mass of the diprotic acid, H₂X is 208.9 g/mol

We'll begin by calculating the number of mole in 45 mL of 0.5 M NaOH.

  • Volume = 45 mL = 45 / 1000 = 0.045 L
  • Molarity of NaOH = 0.1051 M
  • Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.5 × 0.045

Mole of NaOH = 0.0225 mole

Next, we shall determine the number of mole of the diprotic acid, H₂X required to react with 0.0225 mole of NaOH.

H₂X + 2NaOH —> Na₂X + 2H₂O

From the balanced equation above,

2 moles of NaOH reacted with 1 mole of H₂X.

Therefore,

0.0225 mole of NaOH will react with = 0.0225 / 2 = 0.01125 mole of H₂X.

Finally, we shall determine the molar mass of H₂X.

  • Mole of H₂X = 0.01125 mole
  • Mass of H₂X = 2.35 g
  • Molar mass of H₂X =?

Molar mass = mass / mole

Molar mass of H₂X = 2.35 / 0.01125

Molar mass of H₂X = 208.9 g/mol

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