Given Information:
Current = I = 30 A
Diameter = d = 0.326 cm
Electric field = E = 0.062 N/C
Required Information:
Material of jumper cable = ?
Answer:
Copper material with resistivity ρ = 1.727x10⁻⁸ Ωm
Explanation
We can find out the material of the cable by finding the resistivity of the cable
ρ = E/j
The current density j is given by
j = I/A
Where I is the current and A is the area of conductor and is given by
A = πr²
r = d/2
r = 0.326/2
r = 0.163 cm
r = 0.00163 m
A = π(0.00163)²
A = 0.000008346 m²
j = 30/0.000008346
j = 3.59x10⁶ A/m²
The resistivity is given by
ρ = E/j
ρ = 0.062/3.59x10⁶
ρ = 1.727x10⁻⁸ Ωm
This is the resistivity of copper therefore, the material of this jumper cable is copper.
