Answer: The concentration of potassium iodide in the solution is [tex]169.\mu M[/tex]
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Micro molarity of the solution}=\frac{\text{Micro moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]
We are given:
Micro moles of potassium iodide = [tex]67.7\mu mol[/tex]
Volume of solution = 400 m
Putting values in above equation, we get:
[tex]\text{Micro molarity of KI}=\frac{67.7\mu mol\times 1000}{400}\\\\\text{Micro molarity of KI}=169.\mu M[/tex]
Hence, the concentration of potassium iodide in the solution is [tex]169.\mu M[/tex]
