Answer:
Explanation:
THE CORECT QUESTION
A 50.0 mL solution of 0.127 M KOH is titrated with 0.254 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl.
SOLUTION
Get the concentration of the HCl first using titration formula
CA X V A / CB VB = NA/ NB
Equation of reation; KOH + HCl => KCl + H2O
CA = 0.254 M
CB = 0.127
VA = 1/0.254 = 3.937
CA (after the addition) = 0.127 x 50 / 3.937
= 1.612 M
But pH = - Log[hydrogen ion]
= -log 1.612
=
