Answer:
No of turns are 1850.18 turns and length of wire is 162.67 m .
Explanation:
Given :
Magnetic field , [tex]B=2.79\times 10^{-2}\ T.[/tex]
Radius of solenoid , [tex]r = 1.40\ cm=0.014\ m.[/tex]
Current through the solenoid , I = 12 A .
Length of solenoid , L = 40 cm = 0.4 m .
a) . We know ,
Expression of magnetic field is given by :
[tex]B=\mu_o ni\\\\n=\dfrac{B}{\mu_oi}=\dfrac{2.79\times 10^{-2}}{4\pi\times 10^{-7} \times 12}=1850.18\ turns.[/tex]
b) .
Wire required , [tex]l=(2\pi r)n=2\times 3.14\times 0.014\times 1850.18=162.67\ m.[/tex]
Hence, this is the required solution.
