Answer:
The tension in the strap is 74.82 N.
Explanation:
Given that,
Angle between the horizontal and the suitcase is 36 degrees.
The distance traveled by the suitcase is 15 meters.
Let the work done by the suitcase is 908 J. We know that the work done in the vector form is given by :
[tex]W=Fd\ \cos\theta\\\\908=F\times 15\times cos(36)\\\\F=74.82\ N[/tex]
So, the tension in the strap is 74.82 N. Hence, this is the required solution.