Answer:
Step-by-step explanation:
Hello!
You have two variables of interest.
X₁: Weight of a popcorn bag.
It's mean is μ= 3.05 ounces and it's standard deviation δ= 0.02 ounces.
X₂: Weight of a potato chips bag.
With mean μ= 5.07 ounces and standard deviation δ= 0.04 ounces.
A bag of popcorn is randomly selected and its weight is X₁= 3.02 and a bag of potato chips is randomly selected with weight X₂= 5.03.
Since these two values are from completely different distributions, you cannot compare them, but if you convert these values to their equivalent Z value. For this, you will subtract the mean of their distribution and dive them by their standard deviation.
Z= (X-μ)/δ ~N(0;1)
Bag of popcorn: Z=(3.02-3.05)/0.02= -1.5
The selected bag of popcorn is 1.5δ away from the mean.
I hope it helps!
