Answer:
The resistance of the motor is 8.91 ohms.
Explanation:
Given that,
Voltage of the socket, V = 120 V
Current, I = 2.4 A
Back emf generated by the electric motor is, E = 98.6 V
We need to find the coil resistance of the motor. The new emf on the vacuum cleaner is
[tex]V'=V-E[/tex]
[tex]V'=120\ V-98.6\ V\\\\V'=21.4\ volts[/tex]
The resistance of the motor is given by :
[tex]V'=IR\\\\R=\dfrac{V'}{I}\\\\R=\dfrac{21.4\ V}{2.4\ A}\\\\R= 8.91\ \Omega[/tex]
So, the resistance of the motor is 8.91 ohms. Hence, this is the required solution.
