Answer:
D) 7500 N/m
Explanation:
Given :
Work done by the spring, W = 6 J
Stretch in the spring, x = 4 cm = 0.04 m
Consider k be the spring constant.
The relation between work done and stretch of the spring is:
[tex]W=\frac{1}{2}kx^{2}[/tex]
Substitute the suitable values in the above equation.
[tex]6=\frac{1}{2}k(0.04)^{2}[/tex]
[tex]k=\frac{12}{1.6\times10^{-3} }[/tex]
k = 7500 N/m
