Answer:
(e) none of the above
Explanation:
work done is the product of applied force and vertical distance.
work done = Fd
F₁d₁ = F₂d₂
[tex]F_2 = \frac{F_1*d_1}{d_2}[/tex]
given;
vertical distance a clerk can lift containers , d₁ = 1 m
vertical distance rolled along a ramp, d₂ = 3 m
substitute these values in the above equation;
[tex]F_2 = \frac{F_1*1}{3}= \frac{1}{3}*F_1[/tex]
Therefore, the applied force is one-third the original value.
The correct option is (e) none of the above.