Respuesta :
Answer:
[tex]HSO_3^-[/tex]: conjugate acid of [tex]SO_3^{2-}[/tex]
[tex]CH_3NH_2[/tex] : conjugate base of [tex]CH_3NH_3^+[/tex]
[tex]SO_3^{2-}[/tex] : conjugate base of [tex]HSO_3^-[/tex]
[tex]CH_3NH_3^+[/tex] : conjugate acid of [tex]CH_3NH_2[/tex]
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
[tex]HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+[/tex]
Here in forward reaction [tex]CH_3NH_2[/tex] is accepting a proton, thus it is considered as a base and after accepting a proton, it forms [tex]CH_3NH_3^+[/tex] which is a conjugate acid.
And [tex]HSO_3^-[/tex] is losing a proton, thus it is considered as an acid and after loosing a proton, it forms [tex]SO_3^{2-}[/tex] which is a conjugate base.
Similarly in the backward reaction, [tex]CH_3NH_3^+[/tex] is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms [tex]CH_3NH_2[/tex] which is a conjugate base.
And [tex]SO_3^{2-}[/tex] is accepting a proton, thus it is considered as a base and after accepting a proton, it forms [tex]HSO_3^{-}[/tex] which is a conjugate acid.
