Respuesta :
Answer:
Okay so the first one is the same as the other which is 1,716
and since 13C6 = 13P6 / 6 I think that the second one is 10,296
I will edit when I figure out how to put them into exptential form. I havent done that in a while.
Part one:
6!(13-1)= 18,564
There are 18,564 possible combinations.
Part two:
(13-6)!=1,235,520
There are 1,235,520 possible combinations without repetition and specific order.