Answer:
(1) 0.016597
(2) 0.040978
(3) 0.080277
(4) 0.341909
Step-by-step explanation:
1) probability of one or more catastrophes in the next: two missions =1-P(no catastrophes)=1-(119/120)2 =0.016597
2) probability of one or more catastrophes in the next five missions =1-(119/120)5 =0.040978
3) probability of one or more catastrophes in the next ten missions =1-(119/120)10 =0.080277
4) probability of one or more catastrophes in the next fifty missions =1-(119/120)50 =0.341909