Answer:
Ann will have 36 different options
Explanation:2
This can be solved using combination.
nCr = n!/ (n-r)! × r!
To buy one coat out of 6 coats, Ann has; 6C1 options.
6Ç1 = 6!/ (6-1)! × 1! = 6 options
To buy one hat out of 6 hats, Ann has; 6C1 options
6C1 = 6 options
If Ann decides to buy one coat and one hat, from 6 coats and 6 hats;
Number of options = 6C1 × 6C1 = 6×6 = 36 options.
Therefore, Ann has 36 different options.
