A DVD with an initial angular speed of 4.0 rad/s accelerates at a rate of 2.0 rad/s2 , causing the DVD to slow down its rotation. What angular distance has the DVD rotated through before coming to rest?

Respuesta :

Answer:

4 rad =229º

Explanation:

  • If we assume that the angular acceleration is constant, we  an find the angular distance rotated, using a kinematic equation very similar to the one used for  linear displacement, as follows:

         [tex]\omega_{f} ^{2} -\omega_{0} ^{2} = 2* \alpha * \Delta \theta[/tex]

  • As the DVD finally comes to rest, this means that  ωf = 0.
  • Replacing ω₀ and α by the respective givens, we can solve for Δθ, as follows:

       [tex]\Delta \theta = \frac{\omega_{0} ^{2} }{2*\alpha} = \frac{(4rad/sec)^{2} }{2*(2.0 rad/sec2)} = 4 rad[/tex]

Explanation:

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