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Calculate the amount of heat required to completely sublime 57.0 g of solid dry ice (CO2) at its sublimation temperature. The heat of sublimation for carbon dioxide is 32.3 kJ/mol.

Respuesta :

adetoseen

Answer:

41.48KJ

Explanation:

the amount of heat(q)=nΔ[tex]H_{sub}[/tex]

n represents the number of moles of the substance

n=[tex]\frac{mass of CO_{2} }{Molar mass of CO_{2} }[/tex]

mass of carbondioxide = 57g

the molar mass of carbondioxide is obtained by adding the atomic mass of the individual elements present

atomic mass of carbon = 12g

atomic mass for oxygen = 16 × 2 =32g

Molar mass of carbondioxide =  12 + 32 = 44g/mole

∴ n = 57÷44

n = 1.2955moles

Δ[tex]H_{sub}[/tex] represents the heat of sublimation for the substance in that sublimation process = 32.3kJ/mol

the amount of heat (q) = 1.2955 × 32.3

q= 41.84KJ

the amount of heat required to completely sublime 57g of carbondioxide is 41.48KJ

asuwafohjames

Answer:

41.83 J.

Explanation:

The amount of heat required to completely sublime CO₂ is

Q = cm' .................. Equation 1

Where Q = Amount of heat required to sublime CO₂, c = heat of sublimation of CO₂, m' = number of moles of CO₂.

Molar mass of CO₂ = 12 + (16×2) = 12×32 = 44 g/mole,

If 1 mole of CO₂ contains a mass of 44 g,

57/44 moles of CO₂ will contain a mass of 57 g.

1.295 moles.

Given: c = 32.3 kJ/mol, n = 1.295 mol.

Substitute into equation 1

Q = 32.3(1.295)

Q = 41.83 J.

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