Answer / explanation :
To solve this problem, since we are given the number of grams, we can use this formula to calculate for number of mole
n = m / Mm
n - number of mole
m - number of mass
Mm - number of molar mass
Mm =
K - 39.0983
S - 28.0855
O - 15.999
K2SO4
Molar mass of K2SO4 = 39.0983 * 2 + 28.0855 + 15.999 * 4
Note : there are 2 atoms of K and 4 atoms of O, 1 atom of S in the compound
Mm = 78.1966 + 28.0855 + 63.996
= 170.2781g/mol
n = 10.95g/170.2781g/mol
= 0.0643mol
The number of atom = number of mole * the number of avogadros constant (6.023 * 10^23)
= 0.0643 * 6.023 * 10^23
= 3.873 * 10^22 atoms
Answer: 3.79x10²² atoms K2SO4
Explanation: The solution to find the atoms of K2SO4 are as follows.
First find the moles of K2SO4.
10. 95 g K2SO4 x 1 mole K2SO4 / 174 g K2SO4
= 0.063 mole K2SO4
Next find the number of atoms using the Avogadro's number.
0.063 moles K2SO4 x 6.022x10 ²³ atoms K2SO4 / 1 mole K2SO4
= 3.79x10²² atoms K2SO4
