Respuesta :
Answer:
i) [tex] \bar X = \frac{\sum_{i=1}^n X_i f_i}{\sum_{i=1}^n f_i}[/tex]
And replacing we got:
[tex] \bar X = \frac{0*7 + 1*4 + 2*2 + 3*5 + 4*3 + 5*3}{7+4+2+5+3+3}= \frac{50}{24}= 2.083[/tex]
ii) For this case we have a total of 24 values and we can calculate the median from the grouped data so we have the following values:
0,0,0,0,0,0,0,1,1,1,1,2,2,3,3,3,3,3,4,4,4,5,5,5
And we can calculate the median from the position 12 and 13 from the data ordered and we got:
[tex] Median = \frac{2+2}{2}= 2[/tex]
Step-by-step explanation:
For this case we have the following data:
Aptitude Frequency
0 7
1 4
2 2
3 5
4 3
5 3
Part i
For this case we can calculate the mean with the following formula:
[tex] \bar X = \frac{\sum_{i=1}^n X_i f_i}{\sum_{i=1}^n f_i}[/tex]
And replacing we got:
[tex] \bar X = \frac{0*7 + 1*4 + 2*2 + 3*5 + 4*3 + 5*3}{7+4+2+5+3+3}= \frac{50}{24}= 2.083[/tex]
Part ii
For this case we have a total of 24 values and we can calculate the median from the grouped data so we have the following values:
0,0,0,0,0,0,0,1,1,1,1,2,2,3,3,3,3,3,4,4,4,5,5,5
And we can calculate the median from the position 12 and 13 from the data ordered and we got:
[tex] Median = \frac{2+2}{2}= 2[/tex]