Respuesta :
Answer:
Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) → PbSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)
Explanation:
Let's consider the molecular equation between aqueous Pb(NO₃)₂ with aqueous Na₂SO₄ to form solid PbSO₄ and aqueous NaNO₃.
Pb(NO₃)₂(aq) + Na₂SO₄(aq) → PbSO₄(s) + 2 NaNO₃(aq)
The complete ionic equation includes all the ions and the molecular species.
Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) → PbSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)
The complete ionic equation to show the reaction of aqueous Pb(NO₃)₂ with aqueous sodium sulfate, Na₂SO₄ to form solid PbSO₄ and aqueous sodium nitrate, NaNO₃ is
Pb²⁺(aq) + 2NO₃⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) —> PbSO₄(s) + 2Na⁺(aq) + 2NO₃⁻(aq)
We'll begin by writing the dissociation equation for Pb(NO₃)₂ and Na₂SO₄. This is illustrated below:
Pb(NO₃)₂(aq) —> Pb²⁺(aq) + 2NO₃⁻(aq)
Na₂SO₄(aq) —> 2Na⁺(aq) + SO₄²⁻(aq)
Combine the two equations to obtain the complete ionic equation.
Pb(NO₃)₂(aq) + Na₂SO₄(aq) —>
Pb²⁺(aq) + 2NO₃⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) —> PbSO₄(s) + 2Na⁺(aq) + 2NO₃⁻(aq)
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