Answer:
[tex]\frac{du}{dt} = 1.515[/tex]
[tex]\frac{dv}{dt} = 5.511[/tex]
Explanation:
The acceleration field is obtained by deriving the components in function of the time. That is to say:
[tex]\frac{du}{dt}=2.05\cdot \frac{dx}{dt}+0.656\cdot \frac{dy}{dt}\\\frac{dv}{dt} = -2.18\cdot \frac{dx}{dt} -2.05\cdot \frac{dy}{dt}[/tex]
Where [tex]\frac{dx}{dt} = u[/tex] and [tex]\frac{dy}{dt} = v[/tex].
The velocity components at given point are, respectively:
[tex]u = 2.424[/tex]
[tex]v=-5.266[/tex]
Lastly, the acceleration components are found:
[tex]\frac{du}{dt} = 1.515[/tex]
[tex]\frac{dv}{dt} = 5.511[/tex]
