The strain hardening exponent for the given alloy is; n = 0.398
From the hollomon equation, we know that;
εⁿ = σ/K
Where;
ε is true strain
σ is true stress
K is a constant
n is strain hardening hardening exponent
Now we are given;
True strain; ε = 0.1
True stress; σ = 415 MPa
K = 1035 MPa
Thus, Plugging in the relevant values into the hollomon equation gives;
0.1ⁿ = 415/1035
0.1ⁿ = 0.4
Thus;
n In 0.1 = In 0.4
n = (In 0.4)/(In 0.1)
n = 0.398
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