contestada

the equation of line j is y=-x+1/9. parallel to line j is line k, which passes through the point (10,-4). what is the equation of line k

Respuesta :

igoroleshko156

Answer:

y = -x + 6

Step-by-step explanation:

Use point slope form:  (y - y1) = m(x - x1)

m is -1

Step 1:  Plug in

(y - (-4)) = -1(x - 10)

y + 4 - 4 = -x + 10 - 4

y = -x + 6

Answer:  y = -x + 6

Otras preguntas