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Consider the balanced equation of aluminum reacting with sulfuric acid. 2 A l + 3 H 2 S O 4 ⟶ A l 2 ( S O 4 ) 3 + 3 H 2 Determine how many atoms of each element are present on each side of the arrow.

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Eduard22sly

Answer:

Al = 2 atoms.

H = 6atoms.

S = 3 atom.

O = 12 atoms

Explanation:

2Al + 3H2SO4 —> Al2(SO4)3 + 3H2

From the balanced equation, the number of atoms of the different elements present on both sides as

Al = 2 atoms.

H = 6 atoms.

S = 3 atoms.

O = 12 atoms

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