solution is prepared by adding 18 mL of 0.200 M Fe(NO3)3and 2 mL of 0.0020 M KSCN. Calculate the initial concentrations of Fe3 and SCN-in the solution

Respuesta :

Answer : The initial concentration of [tex]Fe^{3+}[/tex] and [tex]SCN^-[/tex] in the solution are, 0.200 M and 0.0020 M respectively.

Explanation :  Given,

Concentration of [tex]Fe(NO_3)_3[/tex] = 0.200 M

Concentration of [tex]KSCN[/tex] = 0.0020 M

As, 1 mole of  [tex]Fe(NO_3)_3[/tex] dissociate then it gives 1 mole of [tex]Fe^{3+}[/tex] ion and 3 moles of [tex]NO_3^-[/tex] ion.

So, 0.200 M of  [tex]Fe(NO_3)_3[/tex] dissociate then it gives 0.200 M of [tex]Fe^{3+}[/tex] ion and (3×0.200 M) of [tex]NO_3^-[/tex] ion.

and,

As, 1 mole of  [tex]KSCN[/tex] dissociate then it gives 1 mole of [tex]K^{+}[/tex] ion and 1 mole of [tex]SCN^-[/tex] ion.

So, 0.0020 M of  [tex]KSCN[/tex] dissociate then it gives 0.0020 M of [tex]K^{+}[/tex] ion and 0.0020 M of [tex]SCN^-[/tex] ion.

Thus, the initial concentration of [tex]Fe^{3+}[/tex] and [tex]SCN^-[/tex] in the solution are, 0.200 M and 0.0020 M respectively.