Answer:
Step-by-step explanation:
In one hour, the population has increased from 100 to 570.
The population becomes [tex]\frac{570}{100} \times 100= 570[/tex]% of 100.
Hence, according to our observation, we can tell that the population of the bacteria grows up to 570% of previous hour.
(a)
The number of bacteria after t hours can be represented as [tex]p(t) = (\frac{570}{100} )^{t} \times 100[/tex].
(b)
After 4 hours, the number of bacteria will be [tex](\frac{570}{100} )^{4} \times 100 = 105560.01[/tex].
(c)
The derivative of p(t) is [tex]100\times ln(5.7) \times (5.7)^t[/tex].
At t = 4, the value will be 183723.6268 ≅ 183724.
(d)
The population will be 10,000 that is p(t) = 10000.
[tex](5.7)^t \times100 = 10000\\(5.7)^t = 100\\t = 2.64594 = 2.6[/tex].