Respuesta :
Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Explanation :
First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.
As, 207.2 g of lead contains [tex]6.022\times 10^{23}[/tex] atoms
So, 5.5 g of lead contains [tex]\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}[/tex] atoms
and,
As, 118.71 g of lead contains [tex]6.022\times 10^{23}[/tex] atoms
So, 94.5 g of lead contains [tex]\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}[/tex] atoms
Now we have to calculate the percent composition of Pb and Sn in atom.
[tex]\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100[/tex]
[tex]\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%[/tex]
and,
[tex]\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100[/tex]
[tex]\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%[/tex]
Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
