Answer:
The required potential difference is [tex]4.95 \times 10^{4}~V[/tex].
Explanation:
We know, electric field is nothing but the negative gradiant of potential. Mathematically, in three-dimension,
[tex]\vec{E} = -\vec{\nabla}V[/tex]
In one dimension, the magnitude of the electric field is
[tex]E = \dfrac{V}{x}[/tex]
where '[tex]V[/tex]' is the applied voltage and '[tex]x[/tex]'is the distance through which the voltage is applied.
Given, [tex]V = 5.78 \times 10^{5}~N~C^{-1}~ and~ x = 8.56~cm = 0.0856~m[/tex].
So the required potential difference is
[tex]V = E \times x = 5.78 \times 10^{5}~N~C^{-1} \times 0.0856~m = 4.95 \times 10^{4}~V[/tex]
