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Complete and balance the molecular equation, including phases, for the reaction of aqueous copper (ll) chloride, CuCl2, and aqueous potassium phosphate, K3PO4.

Cu Cl,(aq) K,PO4(aq) -->

Enter the balanced net ionic equation, including phases, for this reaction

Respuesta :

[tex]3{Cu^2^+}(aq.) + 2{PO_4^3^+}(aq)[/tex] ⇒ [tex]Cu_3(PO)_4[/tex]

Explanation:

Reaction Type

It is double displacement reaction.

Cupric Chloride + Tribasic Potassium Phosphate ⇒ Cupric Phosphate + Potassium Chloride

Reactants

  1. Cupric Chloride[tex](CuCl_2)[/tex]
  2. Tribasic Potassium Phosphate [tex](K_3PO_4)[/tex]

Products

  1. Cupric Phosphate[tex](Cu_3(PO_4)_2)[/tex]
  2. Potassium Chloride [tex](KCl)[/tex]

The reaction is as follows -

[tex]CuCl_2 + K_3PO_4[/tex] = [tex]Cu_3(PO_4)_2 + KCl[/tex]

∴ The Balanced Chemical Equation  is as follows -

[tex]3CuCl_2 + 2K_3PO_4[/tex] = [tex]Cu_3(PO_4)_2 + 6KCl[/tex]

The Net ionic equation including the phases is as follows -

[tex]3{Cu^2^+}(aq.) + 2{PO_4^3^+}(aq)[/tex] ⇒ [tex]Cu_3(PO)_4[/tex]

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