Respuesta :
Answer:
Step-by-step explanation:
Given that you had a box of cards with 6 red suited cards and 4 black suited cards. Further suppose that the first card drawn was red and was not replaced, and the second card drawn was black
Since without replacement, we find I card red will not be replaced.
So for drawing second card, available cards would be 5 red and 4 black.
The probability of drawing the first (red) card is ______
= no of red cards/total cards
= [tex]\frac{6}{6+4} \\=0.60[/tex]
The probability of drawing the second (black) card is ______.
= no of black cards available/total cards avaialble
= [tex]\frac{4}{5+4} \\=0.4444[/tex]
