Answer:
diameter of transmission is 3.473 mm
Explanation:
given data
current = 300 A
total wire length = 1.0 m
voltage drop = 0.55 V
solution
as here Resistivity of copper is = 1.68 × [tex]10^{-8}[/tex] ohm- m
so we get here resistance of wire that is
resistance = [tex]\frac{V}{I}[/tex] ..............1
R = [tex]\frac{0.55}{310}[/tex]
R = 1.774 × [tex]10^{-3}[/tex] ohm
and now we get diameter of wire that is
R = [tex]\frac{\rho l}{A}[/tex] .............2
[tex]\pi \frac{d^2}{4} = \frac{\rho l}{R}[/tex]
d² = [tex]\frac{4\rho l}{\pi R}[/tex] ...............3
put here value
d² = [tex]\frac{4\times 1.68\times 10^{-8} \times 1}{\pi \times 1.774\times 10^{-3}}[/tex]
d = [tex]\sqrt{12.064\times 10^{-6}}[/tex]
d = 3.473 × [tex]10^{-3}[/tex] m
d = 3.473 mm
so diameter of transmission is 3.473 mm
