A 5.00-kg squid initially at rest ejects 0.250 kg of fluid with a velocity of 10.0 m/s. What is the recoil velocity of the squid if the ejection is done in 0.100 s and there is a 5.00-N frictional force opposing the squid’s movement?

Respuesta :

Answer:

[tex]v_{squid} = 0.4\,\frac{m}{s}[/tex] in the negative direction.

Explanation:

The physical modelled is analyzed by using the Principle of Moment Conservation and Impact Theorem. Let consider that fluid travels in the positive direction:

[tex]F\cdot \Delta t = m_{fluid}\cdot v_{fluid}-m_{squid}\cdot v_{squid}[/tex]

Now, the recoil velocity of the squid is obtained

[tex]v_{squid}= \frac{m_{fluid}\cdot v_{fluid}-F\cdot \Delta t}{m_{squid}}[/tex]

[tex]v_{squid}=\frac{(0.250\,kg)\cdot (10\,\frac{m}{s} )-(5\,N)\cdot(0.1\,s)}{5\,kg}[/tex]

[tex]v_{squid} = 0.4\,\frac{m}{s}[/tex]