Respuesta :
Answer:
(a) Magnetic field at the center of the loop is 4.08 x 10⁻⁵ T
(b) Magnetic field at the axis of the loop is 5.09 x 10⁻⁹ T
Explanation:
Given :
Diameter of the circular loop = 2 cm
Radius of the circular loop, R = 1 cm = 0.01 m
Current flowing through the circular wire, I = 650 mA = 650 x 10⁻³ A
(a) Magnetic field at the center of circular loop is determine by the relation:
[tex]B=\frac{\mu_{0}I }{2R}[/tex]
Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ T m²/A.
Substitute the suitable values in the above equation.
[tex]B=\frac{4\pi\times10^{-7}\times650\times10^{-3} }{2\times0.01}[/tex]
B = 4.08 x 10⁻⁵ T
(b) Distance from the center of the loop, z = 20 cm = 0.2 m
Magnetic field at the point on the axis of the loop is determine by the relation:
[tex]B=\frac{\mu_{0}IR^{2} }{2(z^{2}+R^{2})^{3/2} }[/tex]
[tex]B=\frac{4\pi\times10^{-7}\times650\times10^{-3}\times (0.01)^{2} }{2((0.2)^{2}+(0.01)^{2})^{3/2} }[/tex]
B = 5.09 x 10⁻⁹ T
