Respuesta :
Explanation:
Formula for maximum efficiency of a Carnot refrigerator is as follows.
[tex]\frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}[/tex] ..... (1)
And, formula for maximum efficiency of Carnot refrigerator is as follows.
[tex]\frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}[/tex] ...... (2)
Now, equating both equations (1) and (2) as follows.
[tex]Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}[/tex] = [tex]Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}[/tex]
[tex]\gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}[/tex]
= [tex]\frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})[/tex]
= [tex]\frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})[/tex]
= 2.5
Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.
