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At the top of a giant swing on the high bar, a 50 kg gymnast’s velocity is 3 m/s, and he is 3.5 m high. What is the gymnast’s total mechanical energy (KE + PE+ SE) at this instant?

Respuesta :

Answer:

Total Mechanical Energy of the gymnast = 1940J = 1.94 kJ

Explanation:

Total Mechanical Energy = KE + PE + SE

Kinetic Energy, [tex]KE = 1/2 MV^{2}[/tex]

[tex]KE = 0.5 * 50 * 3^{2} \\KE = 225 J[/tex]

Potential Energy,

[tex]PE = mgh\\PE = 50 * 9.8 * 3.5\\\\PE=1715 J[/tex]

Strain Energy,

[tex]SE = 1/2 K x^{2}[/tex]

Since there is no force of deformation, x = 0, SE = 0

Total Mechanical Energy = 225 + 1715

Total Mechanical Energy of the gymnast = 1940J = 1.94 kJ