Answer:
the distance of the two cars is moving at rate 20 mi/h
Explanation:
given information:
the speed of first car, v₁ = dx/dt = 16 mi/h
the speed of second car, v₂ = dy/dt = 12 mi/h
time, t = 2 h
to find the rate of the distance between the two car, we use the following formula
dx/dt = 16 mi/h
x(t) = 16t
x(2) = 16 x 2
= 32 mi
dy/dt = 12 mi/h
y(t) = 12t
= 12 x 2
= 24
[tex]s=\sqrt{x^{2}+y^{2} }[/tex]
[tex]=\sqrt{32^{2}+24^{2} }[/tex]
= 40 mi
the rate of the distance at 2h = 40 mi/2 = 20 mi/h
