Answer:
I = 2amps
Explanation:
Parameters given:
I = 4 amps when Vs=40 volts and Is=4 amps;
I =1 amps when Vs=20 volts and Is=0
Determine the value of I when Vs=60 volts and Is = -2 amps
SOLUTION
Note that it is linear
If I = 1 amp when Vs = 20 and Is = 0 then
I = 2 amps when Vs = 40 volts and Is = 0 (linearity).
Hence, I = 2 amps (4–2) when Vs = 0 and Is=4amps (superposition).
thus, we can solve for I;
I = 1(60/20) + 2(–2/4) = 3–1
= 2amps