A water wave is 3m tall. Taking a picture of the wave, you measure 7m between peaks. With your stopwatch, you measure .8 seconds between a peak and a trough. Write the wave function for this water wave. Ignore the initial phi.

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Answer:

The water wave function is given as   [tex]y(x,t) = 3 sin(\frac{2\pi }{7}(x +0.875t))[/tex]                              

Explanation:

Water waves are surface waves, which is a mixture of longitudinal and transverse waves.

The general wave equation is given as;

[tex]y(x,t) = A sin(\frac{2\pi }{\lambda}(x +vt))[/tex]

where;

A is the amplitude = 3 m

λ is one wavelength = 7 m

t is period for one complete oscillation, T = 8 s

v is the velocity of the wave;

for each period, the wave  travels one wavelength, v = λ/T = 7/8 = 0.875m/s

[tex]y(x,t) = 3 sin(\frac{2\pi }{7}(x +0.875t))[/tex]

Therefore, the water wave function is given as [tex]y(x,t) = 3 sin(\frac{2\pi }{7}(x +0.875t))[/tex]