Answer:
Fundamental frequency = 60 Hz
Explanation:
The fundamental frequency can be found by
fo =(f_4*λ_4)/λ_o
Where
λ_o = 2L/1 = 2L
λ_4 = 2L/4 = L/2
fo = (240*L/2)/2L
L cancels out and equation becomes
fo = (240)/4
fo = 60
Therefore, the fundamental frequency of the string is 60 Hz.
Answer:
Explanation:
Given f1 = 60 Hz
Let L be the length of the string vibrating in four loops. so each will represent half wavelength and four loops will be 2 wavelength long.
λn= 2 L/ n where n=1,2,3,4..............
For n=4
λ4 = L/2
To fundamental frequency it should vibrate in one loop so
For n=1
λ1 = 2 L/ 1
we know that f1 × λ1 = f2 × λ2 = f3 × λ3 = f4 × λ4
⇒f1 × λ1 = f4 × λ4
f1 = (f4 × λ4)/λ1
f1 = (240 Hz × L/2) / 2L
f1 = 60 Hz
